What is the derivative of f(x)=3x^2-2cos(x) ?

The derivative of f(x)=3x^2-2cos(x) is 6x+2sin(x)

What is the first derivative of f(x)=3x^2-2cos(x) ?

The first derivative of f(x)=3x^2-2cos(x) is 6x+2sin(x)

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derivative of

f (x) = 3 x^{2} - 2 cos (x)

6 x + 2 sin (x)

Solution steps

\frac{d}{d x} (3 x^{2} - 2 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (2 cos (x))

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

= 6 x - (- 2 sin (x))

Simplify

= 6 x + 2 sin (x)

\frac{d ^{2}}{d x ^{2}} (1)

2 y^{^{''}} + 3 y^{^{'}} + 4 y = 0

\int x - x^{4} d x

\frac{d}{d x} (\frac{5 x - 2}{2 x + 7})

y^{^{''}} - 3 y^{^{'}} - 28 y = 0

What is the derivative of f(x)=3x^2-2cos(x) ?
The derivative of f(x)=3x^2-2cos(x) is 6x+2sin(x)
What is the first derivative of f(x)=3x^2-2cos(x) ?
The first derivative of f(x)=3x^2-2cos(x) is 6x+2sin(x)