What is the solution for y^{''}-4y^'+3y=5e^{3t} ?

The solution for y^{''}-4y^'+3y=5e^{3t} is y=c_{1}e^{3t}+c_{2}e^t+(5e^{3t}t)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-4y^'+3y=5e^{3t}

y^{^{''}} - 4 y^{^{'}} + 3 y = 5 e^{3 t}

y = c_{1} e^{3 t} + c_{2} e^{t} + \frac{5 e ^{3 t} t}{2}

Solution steps

y^{''} (t) - 4 y^{'} (t) + 3 y = 5 e^{3 t}

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{t} + \frac{5 e ^{3 t} t}{2}

y = c_{1} e^{3 t} + c_{2} e^{t} + \frac{5 e ^{3 t} t}{2}

y^{^{'''}} - y^{^{''}} - 9 y^{^{'}} + 9 y = 4 - e^{x} + e^{3 x}

y^{^{''}} + 36 y = 6 cos (6 x) + 9 sin (6 x)

y^{^{''}} + 8 y^{^{'}} + 16 y = 8 sin (2 t)

y^{^{''}} - 4 y = x^{3}

y^{^{''}} + y^{^{'}} = x^{2} + x

What is the solution for y^{''}-4y^'+3y=5e^{3t} ?
The solution for y^{''}-4y^'+3y=5e^{3t} is y=c_{1}e^{3t}+c_{2}e^t+(5e^{3t}t)/2