What is the solution for (D^3+2D^2-5D-6)y=e^{-3x} ?

The solution for (D^3+2D^2-5D-6)y=e^{-3x} is y=c_{1}e^{-x}+c_{2}e^{2x}+c_{3}e^{-3x}+(e^{-3x}x)/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(D^3+2D^2-5D-6)y=e^{-3x}

(D^{3} + 2 D^{2} - 5 D - 6) y = e^{- 3 x}

y = c_{1} e^{- x} + c_{2} e^{2 x} + c_{3} e^{- 3 x} + \frac{e ^{- 3 x} x}{10}

Solution steps

(D^{3} + 2 D^{2} - 5 D - 6) y = e^{- 3 x}

Solve linear ODE:

y = c_{1} e^{- x} + c_{2} e^{2 x} + c_{3} e^{- 3 x} + \frac{e ^{- 3 x} x}{10}

y = c_{1} e^{- x} + c_{2} e^{2 x} + c_{3} e^{- 3 x} + \frac{e ^{- 3 x} x}{10}

y^{^{''}} + 4 y^{^{'}} + 4 y = sin (2 t)

y^{^{''}} + 16 y = 17 sec^{2} (4 t)

y^{^{''}} - y = t, y^{^{'}} (0) = 1

y^{^{''}} + 4 y = 2 sin (x)

2 y^{^{''}} + y^{^{'}} = cos^{2} (x)

What is the solution for (D^3+2D^2-5D-6)y=e^{-3x} ?
The solution for (D^3+2D^2-5D-6)y=e^{-3x} is y=c_{1}e^{-x}+c_{2}e^{2x}+c_{3}e^{-3x}+(e^{-3x}x)/(10)