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Popular >

y^{''}-y^'=-2

Solution

y^{^{''}} - y^{^{'}} = - 2

Solution

y = c_{1} e^{t} + c_{2} + 2 t

Solution steps

y^{''} (t) - y^{'} (t) = - 2

Solve linear ODE:

y = c_{1} e^{t} + c_{2} + 2 t

y = c_{1} e^{t} + c_{2} + 2 t

Graph

Popular Examples

4y+7y^'+2y^{''}=10*cos(4x)

4 y + 7 y^{^{'}} + 2 y^{^{''}} = 10 \cdot cos (4 x)

y^{''}-y^'+y=sin(t)-3e^{2t}

y^{^{''}} - y^{^{'}} + y = sin (t) - 3 e^{2 t}

y^{''}-2y^'+y=3e^t

y^{^{''}} - 2 y^{^{'}} + y = 3 e^{t}

y^{''}+2y^'+y=x^2e^xcos(x)

y^{^{''}} + 2 y^{^{'}} + y = x^{2} e^{x} cos (x)

y^{''}-5y^'+4y=e^x

y^{^{''}} - 5 y^{^{'}} + 4 y = e^{x}

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'=-2 ?
The solution for y^{''}-y^'=-2 is y=c_{1}e^t+c_{2}+2t