What is the solution for y^{''}-10y^'+21y=240e^t ?

The solution for y^{''}-10y^'+21y=240e^t is y=c_{1}e^{7t}+c_{2}e^{3t}+20e^t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-10y^'+21y=240e^t

y^{^{''}} - 10 y^{^{'}} + 21 y = 240 e^{t}

y = c_{1} e^{7 t} + c_{2} e^{3 t} + 20 e^{t}

Solution steps

y^{''} (t) - 10 y^{'} (t) + 21 y = 240 e^{t}

Solve linear ODE:

y = c_{1} e^{7 t} + c_{2} e^{3 t} + 20 e^{t}

y = c_{1} e^{7 t} + c_{2} e^{3 t} + 20 e^{t}

20 \frac{d ^{4} y}{d x ^{4}} + 100 \frac{d ^{2} y}{d x ^{2}} = 139

y^{^{''}} - y = 1, y^{^{'}} (0) = 1

y^{^{''}} + 2 y^{^{'}} - 3 y = 6 x + 5

5 y^{^{''}} + 4 y^{^{'}} + 4 y = 35 e^{- 4 x}

y^{^{'''}} + y^{^{'}} = x sin (x + 1)

What is the solution for y^{''}-10y^'+21y=240e^t ?
The solution for y^{''}-10y^'+21y=240e^t is y=c_{1}e^{7t}+c_{2}e^{3t}+20e^t