What is the first derivative of 8x+7 ?

The first derivative of 8x+7 is 8

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derivative of 8x+7

\frac{d}{d x} (8 x + 7)

8

Solution steps

\frac{d}{d x} (8 x + 7)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) + \frac{d}{d x} (7)

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (7) = 0

= 8 + 0

Simplify

= 8

f (x) = x - 1

\frac{d}{d x} (2 cos^{12} (x))

x \to 0 lim (y^{x})

x \to - 1 + lim (\frac{x + 1}{x ^{3} + 1})