What is the solution for y^{''}-y^'-6y=2x ?

The solution for y^{''}-y^'-6y=2x is y=c_{1}e^{3x}+c_{2}e^{-2x}-x/3+1/18

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y^'-6y=2x

y^{^{''}} - y^{^{'}} - 6 y = 2 x

y = c_{1} e^{3 x} + c_{2} e^{- 2 x} - \frac{x}{3} + \frac{1}{18}

Solution steps

y^{''} (x) - y^{'} (x) - 6 y = 2 x

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- 2 x} - \frac{x}{3} + \frac{1}{18}

y = c_{1} e^{3 x} + c_{2} e^{- 2 x} - \frac{x}{3} + \frac{1}{18}

y^{^{''}} - y^{^{'}} - 6 y = 5 - 6^{x}, y (0) = 2, y^{^{'}} (0) = 4

y^{^{''}} - 2 y^{^{''}} + y = x e^{x} + e^{x}

x^{^{''}} + 16 x = 34 e^{- 2 t} cos (4 t)

x^{^{''}} + 9 x = \frac{sin ( t )}{9}

x^{^{''}} - 6 x + 9 x = 126 t^{2} e^{3 t}

What is the solution for y^{''}-y^'-6y=2x ?
The solution for y^{''}-y^'-6y=2x is y=c_{1}e^{3x}+c_{2}e^{-2x}-x/3+1/18