What is (\partial)/(\partial x)(-e^xln(y)) ?

The answer to (\partial)/(\partial x)(-e^xln(y)) is -ln(y)e^x

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(\partial)/(\partial x)(-e^xln(y))

\frac{\partial}{\partial x} (- e^{x} ln (y))

- ln (y) e^{x}

Solution steps

\frac{\partial}{\partial x} (- e^{x} ln (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - ln (y) \frac{\partial}{\partial x} (e^{x})

Apply the common derivative:

\frac{\partial}{\partial x} (e^{x}) = e^{x}

= - ln (y) e^{x}

e^{2 s}

\frac{( x - 1 )}{( x + 1 )}

x \to 4 - lim (\frac{7 x - 1}{x - 4})

\int \frac{x ^{2} + 12 x - 9}{x ^{3} - 9 x} d x

y^{^{''}} + 13 y^{^{'}} + 36 y = 0, y (0) = 1, y^{^{'}} (0) = 0

What is (\partial)/(\partial x)(-e^xln(y)) ?
The answer to (\partial)/(\partial x)(-e^xln(y)) is -ln(y)e^x