What is the solution for y^{''}+16y=32t ?

The solution for y^{''}+16y=32t is y=c_{1}cos(4t)+c_{2}sin(4t)+2t

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+16y=32t

y^{^{''}} + 16 y = 32 t

y = c_{1} cos (4 t) + c_{2} sin (4 t) + 2 t

Solution steps

y^{''} (t) + 16 y = 32 t

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t) + 2 t

y = c_{1} cos (4 t) + c_{2} sin (4 t) + 2 t

y^{^{''}} + 4 y^{^{'}} + 6 y = 4 e^{- 2 x} cos (x)

y^{^{''}} + 2 y^{^{'}} + 5 y = 24 e^{- t} cos (2 t)

y^{^{''}} - 5 y^{^{'}} + 4 y = \frac{6}{1 + e ^{- 2 x}}

y^{^{''}} + y = c

\frac{d ^{2} y}{d x ^{2}} - 6 \frac{d y}{d x} + 8 y = 8 e^{4 x}

What is the solution for y^{''}+16y=32t ?
The solution for y^{''}+16y=32t is y=c_{1}cos(4t)+c_{2}sin(4t)+2t