What is the solution for y^{''}+5y^'+6y=4+5x ?

The solution for y^{''}+5y^'+6y=4+5x is y=c_{1}e^{-2x}+c_{2}e^{-3x}+(5x)/6-1/36

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+5y^'+6y=4+5x

y^{^{''}} + 5 y^{^{'}} + 6 y = 4 + 5 x

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} + \frac{5 x}{6} - \frac{1}{36}

Solution steps

y^{''} (x) + 5 y^{'} (x) + 6 y = 4 + 5 x

Solve linear ODE:

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} + \frac{5 x}{6} - \frac{1}{36}

y = c_{1} e^{- 2 x} + c_{2} e^{- 3 x} + \frac{5 x}{6} - \frac{1}{36}

y^{^{''}} + 3 y^{^{'}} - 10 y = 20 + 5 e^{3 x}

x^{^{''}} + 4 x^{^{'}} + 14 x = 9 cos (3 t)

y^{^{''}} + 6 y^{^{'}} + 9 y = 4 sin (6 t)

y^{^{''}} + 9 y = t + 3, y (0) = 1, y^{^{'}} (0) = 2

y^{^{''}} - 5 y^{^{'}} + 2 y = 6 t^{2} + 2 t + 7

What is the solution for y^{''}+5y^'+6y=4+5x ?
The solution for y^{''}+5y^'+6y=4+5x is y=c_{1}e^{-2x}+c_{2}e^{-3x}+(5x)/6-1/36