What is the solution for y^{''}+10y^'+16=10 ?

The solution for y^{''}+10y^'+16=10 is y=c_{1}+c_{2}e^{-10t}-(3t)/5

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y^{''}+10y^'+16=10

y^{^{''}} + 10 y^{^{'}} + 16 = 10

y = c_{1} + c_{2} e^{- 10 t} - \frac{3 t}{5}

Solution steps

y^{''} (t) + 10 y^{'} (t) + 16 = 10

Solve linear ODE:

y = c_{1} + c_{2} e^{- 10 t} - \frac{3 t}{5}

y = c_{1} + c_{2} e^{- 10 t} - \frac{3 t}{5}

y^{^{''}} + y - cos (2 x) = 0

y^{^{'''}} - 2 y^{^{''}} + 10 y^{^{'}} = 250 e^{5 x}

y^{^{'''}} - y^{^{''}} - 4 y^{^{'}} + 4 = 0

y^{^{''}} - 9 y = 4 e^{- 5 t}

y^{^{''}} + 4 y = 3 cos (a t)

What is the solution for y^{''}+10y^'+16=10 ?
The solution for y^{''}+10y^'+16=10 is y=c_{1}+c_{2}e^{-10t}-(3t)/5