What is the integral of x^{22}e^{x^{23}} ?

The integral of x^{22}e^{x^{23}} is 1/23 e^{x^{23}}+C

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integral of x^{22}e^{x^{23}}

\int x^{22} e^{x^{23}} d x

\frac{1}{23} e^{x^{23}} + C

Solution steps

\int x^{22} e^{x^{23}} d x

Apply u-substitution

: \int \frac{1}{23} d u

= \int \frac{1}{23} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{23} u

Substitute back

u = e^{x^{23}}

= \frac{1}{23} e^{x^{23}}

Add a constant to the solution

= \frac{1}{23} e^{x^{23}} + C

y = (3 - x^{2}) (x^{3} - 2 x + 1)

\frac{d x}{d t} = \frac{1 - x}{k}

f (x) = sin (7 ln (x))

x y^{^{'}} = y + x^{2} sin (x), y (\frac{π}{2}) = 0

n = 0 \sum \infty (x + 3)^{n}

What is the integral of x^{22}e^{x^{23}} ?
The integral of x^{22}e^{x^{23}} is 1/23 e^{x^{23}}+C