What is the answer to solvefor d,d(t)=-16t^2+32t+40 ?

The answer to solvefor d,d(t)=-16t^2+32t+40 is d=(-16t^2+32t+40)/t ;\quad t\ne 0

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solvefor d,d(t)=-16t^2+32t+40

solve for

d, d (t) = - 16 t^{2} + 32 t + 40

d = \frac{- 16 t ^{2} + 32 t + 40}{t}; t \neq = 0

Solution steps

d (t) = - 16 t^{2} + 32 t + 40

Divide both sides by

t; t \neq = 0

d = \frac{- 16 t ^{2} + 32 t + 40}{t}; t \neq = 0

x^{^{''}} + 81 x = sin (7 t)

y^{^{''}} + 2 y^{^{'}} = t e^{- t}

y^{^{''}} + 4 y^{^{'}} + 5 y = 2 cos (x) - 2 sin (x)

y^{^{''}} - y^{^{'}} - 2 y = 2 x^{2} + 5

(D + 3) y = x + 1

What is the answer to solvefor d,d(t)=-16t^2+32t+40 ?
The answer to solvefor d,d(t)=-16t^2+32t+40 is d=(-16t^2+32t+40)/t ;\quad t\ne 0