What is the derivative of f(x)=(x+2)*(2*x^2-2) ?

The derivative of f(x)=(x+2)*(2*x^2-2) is 6x^2+8x-2

What is the first derivative of f(x)=(x+2)*(2*x^2-2) ?

The first derivative of f(x)=(x+2)*(2*x^2-2) is 6x^2+8x-2

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derivative of

f (x) = (x + 2) \cdot (2 \cdot x^{2} - 2)

6 x^{2} + 8 x - 2

Solution steps

\frac{d}{d x} ((x + 2) (2 x^{2} - 2))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x + 2, g = 2 x^{2} - 2

= \frac{d}{d x} (x + 2) (2 x^{2} - 2) + \frac{d}{d x} (2 x^{2} - 2) (x + 2)

\frac{d}{d x} (x + 2) = 1

\frac{d}{d x} (2 x^{2} - 2) = 4 x

= 1 \cdot (2 x^{2} - 2) + 4 x (x + 2)

Simplify

1 \cdot (2 x^{2} - 2) + 4 x (x + 2) : 6 x^{2} + 8 x - 2

= 6 x^{2} + 8 x - 2

\int - 3 sec (x) tan (x) - 3 csc (x) cot (x) d x

\int \frac{1}{6 x} d x

(t - sin (t))^{^{'}}

\frac{d}{d x} (lo g_{2} (x^{2}))

x^{2}, 2, 5

What is the derivative of f(x)=(x+2)*(2*x^2-2) ?
The derivative of f(x)=(x+2)*(2*x^2-2) is 6x^2+8x-2
What is the first derivative of f(x)=(x+2)*(2*x^2-2) ?
The first derivative of f(x)=(x+2)*(2*x^2-2) is 6x^2+8x-2