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Popular >

y^{''}+2y^'=7

Solution

y^{^{''}} + 2 y^{^{'}} = 7

Solution

y = c_{1} + c_{2} e^{- 2 t} + \frac{7 t}{2}

Solution steps

y^{''} (t) + 2 y^{'} (t) = 7

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 t} + \frac{7 t}{2}

y = c_{1} + c_{2} e^{- 2 t} + \frac{7 t}{2}

Graph

Popular Examples

y^{'''}-y^{''}-y^'+y=(1+e^{-x})

y^{^{'''}} - y^{^{''}} - y^{^{'}} + y = (1 + e^{- x})

y^{''}-4y=(e^{2x}-e^{-2x})/2

y^{^{''}} - 4 y = \frac{e ^{2 x} - e ^{- 2 x}}{2}

(D^2+D+1)y=e^xsin(x)

(D^{2} + D + 1) y = e^{x} sin (x)

(d^2y)/(dx^2)+2(dy)/(dx)+y=e^{-x}

\frac{d ^{2} y}{d x ^{2}} + 2 \frac{d y}{d x} + y = e^{- x}

y^{''}+9y=5sin(3x),y(0)=2,y^'(0)=0

y^{^{''}} + 9 y = 5 sin (3 x), y (0) = 2, y^{^{'}} (0) = 0

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+2y^'=7 ?
The solution for y^{''}+2y^'=7 is y=c_{1}+c_{2}e^{-2t}+(7t)/2