What is the solution for x^{''}-x=-4e^{-t} ?

The solution for x^{''}-x=-4e^{-t} is x=c_{1}e^t+c_{2}e^{-t}+2te^{-t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{''}-x=-4e^{-t}

x^{^{''}} - x = - 4 e^{- t}

x = c_{1} e^{t} + c_{2} e^{- t} + 2 t e^{- t}

Solution steps

x^{''} (t) - x = - 4 e^{- t}

Solve linear ODE:

x = c_{1} e^{t} + c_{2} e^{- t} + 2 t e^{- t}

x = c_{1} e^{t} + c_{2} e^{- t} + 2 t e^{- t}

\frac{d ^{2} y}{d x ^{2}} + y = e^{x}

y^{^{''}} + y^{^{'}} + 6 y = cos (2 x)

0.1 x^{^{''}} + 10 x = 100 sin (c t)

y^{^{''}} - 2 y^{^{'}} + y = x (cosh (x))

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{3 t}, y (0) = - 1, y^{^{'}} (0) = - 4

What is the solution for x^{''}-x=-4e^{-t} ?
The solution for x^{''}-x=-4e^{-t} is x=c_{1}e^t+c_{2}e^{-t}+2te^{-t}