What is the solution for (d^2y)/(dx^2)-y-6=1 ?

The solution for (d^2y)/(dx^2)-y-6=1 is y=c_{1}e^x+c_{2}e^{-x}-7

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(d^2y)/(dx^2)-y-6=1

\frac{d ^{2} y}{d x ^{2}} - y - 6 = 1

y = c_{1} e^{x} + c_{2} e^{- x} - 7

Solution steps

\frac{d ^{2} y}{d x ^{2}} - y - 6 = 1

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- x} - 7

y = c_{1} e^{x} + c_{2} e^{- x} - 7

y^{^{''}} - 2 y^{^{'}} + 2 y = 2 e^{t}

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + 9 y = x e^{x}

y^{^{''}} + y^{^{'}} + 2 y = x + 3, y (0) = 0, y^{^{'}} (0) = 1

y^{^{''}} + y^{^{'}} + 4.25 = 0

y^{^{''}} + 5 y^{^{'}} + 6 y = e^{- 5 x} (- 55 + 68 x - 30 x^{2})

What is the solution for (d^2y)/(dx^2)-y-6=1 ?
The solution for (d^2y)/(dx^2)-y-6=1 is y=c_{1}e^x+c_{2}e^{-x}-7