What is the solution for y^{''}+36y=sin(9x) ?

The solution for y^{''}+36y=sin(9x) is y=c_{1}cos(6x)+c_{2}sin(6x)-1/45 sin(9x)

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y^{''}+36y=sin(9x)

y^{^{''}} + 36 y = sin (9 x)

y = c_{1} cos (6 x) + c_{2} sin (6 x) - \frac{1}{45} sin (9 x)

Solution steps

y^{''} (x) + 36 y = sin (9 x)

Solve linear ODE:

y = c_{1} cos (6 x) + c_{2} sin (6 x) - \frac{1}{45} sin (9 x)

y = c_{1} cos (6 x) + c_{2} sin (6 x) - \frac{1}{45} sin (9 x)

0.5 x^{^{''}} + 3 x^{^{'}} + 4 x = 3 cos (t)

y^{^{''}} + y = sec (2 x)

- 2 y^{^{''}} + 18 y + 2 (3 x^{2} + x + \frac{10}{3}) = 0

D C = 1.5226 D U S

y^{^{''}} - 4 y^{^{'}} + 5 y = 4 e^{- x}

What is the solution for y^{''}+36y=sin(9x) ?
The solution for y^{''}+36y=sin(9x) is y=c_{1}cos(6x)+c_{2}sin(6x)-1/45 sin(9x)