What is the limit as x approaches 2 of 2x^2+4x-5 ?

The limit as x approaches 2 of 2x^2+4x-5 is 11

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limit as x approaches 2 of 2x^2+4x-5

x \to 2 lim (2 x^{2} + 4 x - 5)

11

Solution steps

x \to 2 lim (2 x^{2} + 4 x - 5)

Plug in the value

x = 2

= 2 \cdot 2^{2} + 4 \cdot 2 - 5

Simplify

2 \cdot 2^{2} + 4 \cdot 2 - 5 : 11

= 11

\int_{0}^{4} 400 - 20 t d t

\int (\frac{e ^{x}}{e ^{x} + 1}) d x

\frac{\partial}{\partial x} (y cos (x lo g_{e} (y)))

x \to \infty lim (\frac{2}{0})

\frac{d y}{d t} = - 3 (y - 5)

What is the limit as x approaches 2 of 2x^2+4x-5 ?
The limit as x approaches 2 of 2x^2+4x-5 is 11