What is the solution for (d^2y)/(dt^2)+3/100 (dy)/(dt)=12 ?

The solution for (d^2y)/(dt^2)+3/100 (dy)/(dt)=12 is y=c_{1}+c_{2}e^{-(3t)/(100)}+400t

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(d^2y)/(dt^2)+3/100 (dy)/(dt)=12

\frac{d ^{2} y}{d t ^{2}} + \frac{3}{100} \frac{d y}{d t} = 12

y = c_{1} + c_{2} e^{- \frac{3 t}{100}} + 400 t

Solution steps

\frac{d ^{2} y}{d t ^{2}} + \frac{3}{100} \frac{d y}{d t} = 12

Solve linear ODE:

y = c_{1} + c_{2} e^{- \frac{3 t}{100}} + 400 t

y = c_{1} + c_{2} e^{- \frac{3 t}{100}} + 400 t

y^{^{''}} = - y + cos (2 t)

y^{^{''}} + 5 y^{^{'}} + 2 = 0

y^{^{''}} + 10 y = 10 e^{11 x}

y^{^{''}} + 36 y = 33 cos (5 t), y (0) = 0, y^{^{'}} (0) = 0

D (q) = 2300 - 42 q

What is the solution for (d^2y)/(dt^2)+3/100 (dy)/(dt)=12 ?
The solution for (d^2y)/(dt^2)+3/100 (dy)/(dt)=12 is y=c_{1}+c_{2}e^{-(3t)/(100)}+400t