What is the solution for y^{''}-2y=12x-10 ?

The solution for y^{''}-2y=12x-10 is y=c_{1}e^{sqrt(2)x}+c_{2}e^{-sqrt(2)x}-6x+5

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y^{''}-2y=12x-10

y^{^{''}} - 2 y = 12 x - 10

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - 6 x + 5

Solution steps

y^{''} (x) - 2 y = 12 x - 10

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - 6 x + 5

y = c_{1} e^{2 x} + c_{2} e^{- 2 x} - 6 x + 5

y^{^{''}} + 2 y^{^{'}} + y = 3 (t - 1) e^{- 1}

y^{^{'''}} + y^{^{''}} = x + 1

y^{^{''}} + y - 20 y = (x + 1) e^{x}

y^{^{''}} - 4 y = sin (2 x)

y^{^{''}} - 2 y^{^{'}} + 13 y = 2 e^{3 t}

What is the solution for y^{''}-2y=12x-10 ?
The solution for y^{''}-2y=12x-10 is y=c_{1}e^{sqrt(2)x}+c_{2}e^{-sqrt(2)x}-6x+5