What is the solution for y^{''}+y=2,y(0)=2,y(0)=0 ?

The solution for y^{''}+y=2,y(0)=2,y(0)=0 is y=c_{2}sin(t)+2

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y^{''}+y=2,y(0)=2,y(0)=0

y^{^{''}} + y = 2, y (0) = 2, y (0) = 0

y = c_{2} sin (t) + 2

Solution steps

y^{''} (t) + y = 2

Solve linear ODE:

y = c_{2} sin (t) + 2

y = c_{2} sin (t) + 2

y^{^{''}} - 6 y^{^{'}} - 9 y = x^{2} + e^{x}

x^{^{''}} + 5 x^{^{'}} + 4 x = t^{2} + 3 t + 5

y^{^{''}} - 2 y^{^{'}} + y = 2 sin (3 x)

y^{^{''}} + 16 y = e^{3 t}

y^{^{''}} + 16 y = 2 cos (4 x)

What is the solution for y^{''}+y=2,y(0)=2,y(0)=0 ?
The solution for y^{''}+y=2,y(0)=2,y(0)=0 is y=c_{2}sin(t)+2