What is the solution for y^{''}-2y^'-3y=15te^{2t} ?

The solution for y^{''}-2y^'-3y=15te^{2t} is y=c_{1}e^{3t}+c_{2}e^{-t}-5te^{2t}-10/3 e^{2t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-2y^'-3y=15te^{2t}

y^{^{''}} - 2 y^{^{'}} - 3 y = 15 t e^{2 t}

y = c_{1} e^{3 t} + c_{2} e^{- t} - 5 t e^{2 t} - \frac{10}{3} e^{2 t}

Solution steps

y^{''} (t) - 2 y^{'} (t) - 3 y = 15 t e^{2 t}

Solve linear ODE:

y = c_{1} e^{3 t} + c_{2} e^{- t} - 5 t e^{2 t} - \frac{10}{3} e^{2 t}

y = c_{1} e^{3 t} + c_{2} e^{- t} - 5 t e^{2 t} - \frac{10}{3} e^{2 t}

y^{^{''}} = 3 cos (t) - 2 y

y^{^{''}} + y^{^{'}} - 6 y = 50 x e^{x}

y^{^{''}} + y = t cos (t)

y^{^{''}} - 9 y = 1

y^{^{''}} - 3 y^{^{'}} - 4 y = t^{2}, y (0) = 1, y^{^{'}} (0) = 4

What is the solution for y^{''}-2y^'-3y=15te^{2t} ?
The solution for y^{''}-2y^'-3y=15te^{2t} is y=c_{1}e^{3t}+c_{2}e^{-t}-5te^{2t}-10/3 e^{2t}