What is the tangent of y^2+5x=x^2y-5,(3,5) ?

The tangent of y^2+5x=x^2y-5,(3,5) is y=25x-70

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tangent of y^2+5x=x^2y-5,(3,5)

tangent of

y^{2} + 5 x = x^{2} y - 5, (3, 5)

y = 25 x - 70

Solution steps

Find the slope of

y^{2} + 5 x = x^{2} y - 5 : \frac{d y}{d x} = \frac{2 x y - 5}{2 y - x ^{2}}

Compute the slope of

y^{2} + 5 x = x^{2} y - 5

(3, 5) : m = 25

Find the line with slope m=

25

and passing through

(3, 5) : y = 25 x - 70

y = 25 x - 70

x = y^{2}, x = 3 - 2 y^{2}

\frac{d}{d x} (x^{4} x)

\int \frac{3 x}{x ^{4} + 6 x ^{2} + 5} d x

x \to 0 + lim ((1 + a x)^{\frac{b}{x}})

\frac{d}{d x} (\frac{x ^{3} - 1}{2})

What is the tangent of y^2+5x=x^2y-5,(3,5) ?
The tangent of y^2+5x=x^2y-5,(3,5) is y=25x-70