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Popular >

y^{''}-y^'-a^2=0

Solution

y^{^{''}} - y^{^{'}} - a^{2} = 0

Solution

y = c_{1} e^{t} + c_{2} - a^{2} t

Solution steps

y^{''} (t) - y^{'} (t) - a^{2} = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} - a^{2} t

y = c_{1} e^{t} + c_{2} - a^{2} t

Graph

Popular Examples

y^{''}+6y^'+9y=t+e^{3t}

y^{^{''}} + 6 y^{^{'}} + 9 y = t + e^{3 t}

y^{''}+16y=5cos(4t),y(0)=1,y^'(0)=0

y^{^{''}} + 16 y = 5 cos (4 t), y (0) = 1, y^{^{'}} (0) = 0

y^{''}-9y=4,y^1(0)=e^{-3x}

y^{^{''}} - 9 y = 4, y^{1} (0) = e^{- 3 x}

y^{''''}+9y^{''}=20e^{-t}

y^{^{''''}} + 9 y^{^{''}} = 20 e^{- t}

y^{''''}-y=9t+cos(t)

y^{^{''''}} - y = 9 t + cos (t)

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'-a^2=0 ?
The solution for y^{''}-y^'-a^2=0 is y=c_{1}e^t+c_{2}-a^2t