What is the solution for y^{''}-4y^'+3y=9x^2 ?

The solution for y^{''}-4y^'+3y=9x^2 is y=c_{1}e^{3x}+c_{2}e^x+3x^2+8x+26/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-4y^'+3y=9x^2

y^{^{''}} - 4 y^{^{'}} + 3 y = 9 x^{2}

y = c_{1} e^{3 x} + c_{2} e^{x} + 3 x^{2} + 8 x + \frac{26}{3}

Solution steps

y^{''} (x) - 4 y^{'} (x) + 3 y = 9 x^{2}

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{x} + 3 x^{2} + 8 x + \frac{26}{3}

y = c_{1} e^{3 x} + c_{2} e^{x} + 3 x^{2} + 8 x + \frac{26}{3}

y^{^{''}} + 6 y^{^{'}} - 7 y = 21 x^{2} - 8 x - 30

y^{^{''}} + y^{^{'}} - 2 y = e^{- 2 \cdot x} sin (x)

y^{^{''}} - 2 y^{^{'}} - 3 y = 6 x + 4, y (0) = 1, y^{^{'}} (0) = - 3

y^{^{''}} + 5 y = x e^{x}

y^{^{''}} + 9 y = 5 x, y (0) = 1, y^{^{'}} (0) = 3

What is the solution for y^{''}-4y^'+3y=9x^2 ?
The solution for y^{''}-4y^'+3y=9x^2 is y=c_{1}e^{3x}+c_{2}e^x+3x^2+8x+26/3