en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2y^'-xy+3y^2=0

Solution

x^{2} y^{^{'}} - x y + 3 y^{2} = 0

Solution

y = \frac{x}{3 ln ( x ) + c _{1}}

Solution steps

x^{2} y^{'} (x) - x y + 3 y^{2} = 0

Solve Bernoulli ODE:

y = \frac{x}{3 ln ( x ) + c _{1}}

y = \frac{x}{3 ln ( x ) + c _{1}}

Popular Examples

(d^4)/(dx^4)(x^x)

\frac{d ^{4}}{d x ^{4}} (x^{x})

integral of (sqrt(4-3x)-sqrt(x))

\int (4 - 3 x - x) d x

derivative of x^3-3x^2-9x+11

\frac{d}{d x} (x^{3} - 3 x^{2} - 9 x + 11)

integral of (6e^{-6x})/(2-e^{-6x)}

\int \frac{6 e ^{- 6 x}}{2 - e ^{- 6 x}} d x

integral of e^{1/y}

\int e^{\frac{1}{y}} d y

Frequently Asked Questions (FAQ)

What is the solution for x^2y^'-xy+3y^2=0 ?
The solution for x^2y^'-xy+3y^2=0 is y= x/(3ln(x)+c_{1)}