What is the solution for 1/4 y^{''}+16y=8sin(8t) ?

The solution for 1/4 y^{''}+16y=8sin(8t) is y=c_{1}cos(8t)+c_{2}sin(8t)-2tcos(8t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/4 y^{''}+16y=8sin(8t)

\frac{1}{4} y^{^{''}} + 16 y = 8 sin (8 t)

y = c_{1} cos (8 t) + c_{2} sin (8 t) - 2 t cos (8 t)

Solution steps

\frac{1}{4} y^{''} (t) + 16 y = 8 sin (8 t)

Solve linear ODE:

y = c_{1} cos (8 t) + c_{2} sin (8 t) - 2 t cos (8 t)

y = c_{1} cos (8 t) + c_{2} sin (8 t) - 2 t cos (8 t)

y^{^{''}} - 9 y = sin (x) + 2 cos (x)

y^{^{''}} - 5 y^{^{'}} + 6 y = (x + 1) e^{x}

y^{^{''}} - 3 y^{^{'}} + 2 y = 10

y^{^{''}} - 4 y^{^{'}} + 4 y = 4 (x + 1)

y^{^{''}} - 6 y + 9 y = e^{- 2 x} sin (3 x)

What is the solution for 1/4 y^{''}+16y=8sin(8t) ?
The solution for 1/4 y^{''}+16y=8sin(8t) is y=c_{1}cos(8t)+c_{2}sin(8t)-2tcos(8t)