Solution
Solution
Solution steps
Solve linear ODE:
Graph
Popular Examples
y^{''}+2y= 1/(cos(sqrt(2)x))y^{''}-4y^'+4y=t^{-3}e^{2t}y^{''}+4y^'-32=0y^{''}+16y=e^{5t},y(0)=0,y^'(0)=0y^{''}-4y^'+4y=e^{2x}+x^2
Frequently Asked Questions (FAQ)
What is the solution for y^{''}-2y^'+y=3 ?
The solution for y^{''}-2y^'+y=3 is y=c_{1}e^t+c_{2}te^t+3