en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y^'=3-4x

Solution

y^{^{''}} - y^{^{'}} = 3 - 4 x

Solution

y = c_{1} e^{x} + c_{2} + 2 x^{2} + x

Solution steps

y^{''} (x) - y^{'} (x) = 3 - 4 x

Solve linear ODE:

y = c_{1} e^{x} + c_{2} + 2 x^{2} + x

y = c_{1} e^{x} + c_{2} + 2 x^{2} + x

Graph

Popular Examples

y^{''}+3y+2y=cos(e^x)

y^{^{''}} + 3 y + 2 y = cos (e^{x})

y^{''}+15y^'+7y=sin(x)+cos(x)

y^{^{''}} + 15 y^{^{'}} + 7 y = sin (x) + cos (x)

(y^{''})-2y^'+y=(e^x)/(1+x^2)

(y^{^{''}}) - 2 y^{^{'}} + y = \frac{e ^{x}}{1 + x ^{2}}

y^{''}+2y^'+2y=t^2

y^{^{''}} + 2 y^{^{'}} + 2 y = t^{2}

y^{''}-2y^'+y=e-2x

y^{^{''}} - 2 y^{^{'}} + y = e - 2 x

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'=3-4x ?
The solution for y^{''}-y^'=3-4x is y=c_{1}e^x+c_{2}+2x^2+x