What is the solution for y^{''}+7y=5 ?

The solution for y^{''}+7y=5 is y=c_{1}cos(sqrt(7)t)+c_{2}sin(sqrt(7)t)+5/7

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y^{''}+7y=5

y^{^{''}} + 7 y = 5

y = c_{1} cos (7 t) + c_{2} sin (7 t) + \frac{5}{7}

Solution steps

y^{''} (t) + 7 y = 5

Solve linear ODE:

y = c_{1} cos (7 t) + c_{2} sin (7 t) + \frac{5}{7}

y = c_{1} cos (7 t) + c_{2} sin (7 t) + \frac{5}{7}

x^{^{''}} + x^{^{'}} - 2 x = 8 sin (2 t)

y^{^{''}} - 5 y^{^{'}} + 6 y = (12 x - 7) e^{- x}

y^{^{''}} + 25 y = 20 sin (5 x) + x cos (x)

2 y^{^{''}} - 13 y^{^{'}} + 20 y = 40 x^{2} + 8 x + 10

y^{^{''}} - 2 y^{^{'}} + 10 y = 20 x, y (0) = 0, y^{^{'}} (0) = 0

What is the solution for y^{''}+7y=5 ?
The solution for y^{''}+7y=5 is y=c_{1}cos(sqrt(7)t)+c_{2}sin(sqrt(7)t)+5/7