What is the solution for y^{''}-3y^'+2y=e^{-4x} ?

The solution for y^{''}-3y^'+2y=e^{-4x} is y=c_{1}e^{2x}+c_{2}e^x+1/30 e^{-4x}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-3y^'+2y=e^{-4x}

y^{^{''}} - 3 y^{^{'}} + 2 y = e^{- 4 x}

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{30} e^{- 4 x}

Solution steps

y^{''} (x) - 3 y^{'} (x) + 2 y = e^{- 4 x}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{30} e^{- 4 x}

y = c_{1} e^{2 x} + c_{2} e^{x} + \frac{1}{30} e^{- 4 x}

2 y^{^{''}} + y = cos (t)

y^{^{''}} + y = x^{2} + 1, y (0) = 4, y (1) = 0

y^{^{''}} + y = tan (x), y (0) = 0, y^{^{'}} (0) = 1

y^{^{'''}} + y^{^{'}} = - 2 cos (t)

x^{^{''}} - 5 x^{^{'}} + 6 x = t^{2} e^{3 t}

What is the solution for y^{''}-3y^'+2y=e^{-4x} ?
The solution for y^{''}-3y^'+2y=e^{-4x} is y=c_{1}e^{2x}+c_{2}e^x+1/30 e^{-4x}