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Popular >

y^{''}+y-1=0

Solution

y^{^{''}} + y - 1 = 0

Solution

y = c_{1} cos (t) + c_{2} sin (t) + 1

Solution steps

y^{''} (t) + y - 1 = 0

Solve linear ODE:

y = c_{1} cos (t) + c_{2} sin (t) + 1

y = c_{1} cos (t) + c_{2} sin (t) + 1

Popular Examples

y^{''}-6y^'+5y=te^{2t}

y^{^{''}} - 6 y^{^{'}} + 5 y = t e^{2 t}

y^{''}+4y=6sin(x)

y^{^{''}} + 4 y = 6 sin (x)

y^{'''}-5y^{''}+3y^'+9=0

y^{^{'''}} - 5 y^{^{''}} + 3 y^{^{'}} + 9 = 0

y^{''}-2y^'+y=-1/(x^2)e^x

y^{^{''}} - 2 y^{^{'}} + y = - \frac{1}{x ^{2}} e^{x}

y^{''}+1/8 y^'+4y=3cos(6t)

y^{^{''}} + \frac{1}{8} y^{^{'}} + 4 y = 3 cos (6 t)

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+y-1=0 ?
The solution for y^{''}+y-1=0 is y=c_{1}cos(t)+c_{2}sin(t)+1