What is area x/((x^2+5x+6)),0,1 ?

The answer to area x/((x^2+5x+6)),0,1 is (ln(65536/59049))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area x/((x^2+5x+6)),0,1

area

\frac{x}{( x ^{2} + 5 x + 6 )}, 0, 1

\frac{ln ( \frac{65536}{59049} )}{2}

Decimal Notation

0.05211 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} \frac{∣ x ∣}{∣ x ^{2} + 5 x + 6 ∣} d x

Solve

\int_{0}^{1} \frac{∣ x ∣}{∣ x ^{2} + 5 x + 6 ∣} d x : \frac{ln ( \frac{65536}{59049} )}{2}

The area is:

= \frac{ln ( \frac{65536}{59049} )}{2}

\int e^{- θ x} d x

\frac{d}{d x} (x + y - z)

f (x) = e^{5 x}

\int 2 x^{3} 1 + x^{2} d x

\frac{d y}{d t} = \frac{1}{( y + 2 ) ^{2}}, y (0) = 1

What is area x/((x^2+5x+6)),0,1 ?
The answer to area x/((x^2+5x+6)),0,1 is (ln(65536/59049))/2