What is the answer to solvefor y,(d^2+5d+6)y=(d+1)6t^2 ?

The answer to solvefor y,(d^2+5d+6)y=(d+1)6t^2 is y=((d+1)*6t^2)/(d^2+5d+6);\quad d\ne-2,d\ne-3

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solvefor y,(d^2+5d+6)y=(d+1)6t^2

solve for

y, (d^{2} + 5 d + 6) y = (d + 1) 6 t^{2}

y = \frac{( d + 1 ) \cdot 6 t ^{2}}{d ^{2} + 5 d + 6}; d \neq = - 2, d \neq = - 3

Solution steps

(d^{2} + 5 d + 6) y = (d + 1) \cdot 6 t^{2}

Divide both sides by

d^{2} + 5 d + 6; d \neq = - 2, d \neq = - 3

y = \frac{( d + 1 ) \cdot 6 t ^{2}}{d ^{2} + 5 d + 6}; d \neq = - 2, d \neq = - 3

y^{^{''}} - 6 y^{^{'}} + 10 y = 10 x^{2} + 8 x

y^{^{''}} + y^{^{'}} = 8 x^{2}

y^{^{''}} + y^{^{'}} - 6 y = e^{4 x}

y^{^{''}} - 3 y^{^{'}} = 4 x

y^{^{''}} + y^{^{'}} + y = e^{- t}

What is the answer to solvefor y,(d^2+5d+6)y=(d+1)6t^2 ?
The answer to solvefor y,(d^2+5d+6)y=(d+1)6t^2 is y=((d+1)*6t^2)/(d^2+5d+6);\quad d\ne-2,d\ne-3