What is the answer to solvefor d,d(x)=sqrt((3x-2)/(x+1)) ?

The answer to solvefor d,d(x)=sqrt((3x-2)/(x+1)) is d=(sqrt(3x-2))/(xsqrt(x+1));\quad x\ne 0

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solvefor d,d(x)=sqrt((3x-2)/(x+1))

solve for

d, d (x) = \frac{3 x - 2}{x + 1}

d = \frac{3 x - 2}{x x + 1}; x \neq = 0

Solution steps

d (x) = \frac{3 x - 2}{x + 1}

Divide both sides by

x; x \neq = 0

d = \frac{3 x - 2}{x x + 1}; x \neq = 0

y^{^{''}} - 4 y^{^{'}} + 4 y = 2 x^{2} - 4 x + 2

\frac{d ^{2} y}{d x ^{2}} - 6 \frac{d y}{d x} = 37 sin (x)

y^{^{''}} - 7 y^{^{'}} + 10 y = e^{x}

y^{^{''}} + k y = g - 6 t, y (0) = 0, y^{^{'}} (0) = 0

y^{^{''}} + 8 y^{^{'}} + 16 y = 8 sin (4 x)

What is the answer to solvefor d,d(x)=sqrt((3x-2)/(x+1)) ?
The answer to solvefor d,d(x)=sqrt((3x-2)/(x+1)) is d=(sqrt(3x-2))/(xsqrt(x+1));\quad x\ne 0