What is the solution for y^{''}+2y^'-3y=-15x^2+26x-3 ?

The solution for y^{''}+2y^'-3y=-15x^2+26x-3 is y=c_{1}e^x+c_{2}e^{-3x}+5x^2-2x+3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+2y^'-3y=-15x^2+26x-3

y^{^{''}} + 2 y^{^{'}} - 3 y = - 15 x^{2} + 26 x - 3

y = c_{1} e^{x} + c_{2} e^{- 3 x} + 5 x^{2} - 2 x + 3

Solution steps

y^{''} (x) + 2 y^{'} (x) - 3 y = - 15 x^{2} + 26 x - 3

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- 3 x} + 5 x^{2} - 2 x + 3

y = c_{1} e^{x} + c_{2} e^{- 3 x} + 5 x^{2} - 2 x + 3

y^{^{''}} + 6 y^{^{'}} + 5 y = 5 x + 1

y^{^{''}} + 17 y^{^{'}} + 72 y = 4 x e^{x}

y^{^{''}} + 25 y = 4 sec (5 x)

\frac{d ^{2} v}{d x ^{2}} - k^{2} v = k^{2} n

y^{^{'''}} + 12 y^{^{''}} + 48 y^{^{'}} + 64 y = 9 e^{- 4 x}

What is the solution for y^{''}+2y^'-3y=-15x^2+26x-3 ?
The solution for y^{''}+2y^'-3y=-15x^2+26x-3 is y=c_{1}e^x+c_{2}e^{-3x}+5x^2-2x+3