What is the derivative of 3x^2+4x+5 ?

The derivative of 3x^2+4x+5 is 6x+4

What is the first derivative of 3x^2+4x+5 ?

The first derivative of 3x^2+4x+5 is 6x+4

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\frac{d}{d x} (3 x^{2} + 4 x + 5)

6 x + 4

Solution steps

\frac{d}{d x} (3 x^{2} + 4 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (4 x) + \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 6 x + 4 + 0

Simplify

= 6 x + 4

x \to 0 lim (\frac{x ^{2}}{1 + x ^{2}})

3 (t - π)

x \to \infty lim ((1 - 5 x)^{\frac{5}{x}})

x \to \frac{1}{2} lim (2 x + 7)

\frac{d}{d x} (cos (2 x) - x ln (x))

What is the derivative of 3x^2+4x+5 ?
The derivative of 3x^2+4x+5 is 6x+4
What is the first derivative of 3x^2+4x+5 ?
The first derivative of 3x^2+4x+5 is 6x+4