What is the solution for y^{''}-y=1.7sin(t) ?

The solution for y^{''}-y=1.7sin(t) is y=c_{1}e^t+c_{2}e^{-t}-0.85sin(t)

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y^{''}-y=1.7sin(t)

y^{^{''}} - y = 1.7 sin (t)

y = c_{1} e^{t} + c_{2} e^{- t} - 0.85 sin (t)

Solution steps

y^{''} (t) - y = 1.7 sin (t)

Solve linear ODE:

y = c_{1} e^{t} + c_{2} e^{- t} - 0.85 sin (t)

y = c_{1} e^{t} + c_{2} e^{- t} - 0.85 sin (t)

y^{^{''}} + y^{^{'}} - 12 y = 2 e^{5 t}

\frac{1}{2} x^{^{''}} + 2 x^{^{'}} + 4 x = 20 cos (t)

2 y^{^{''}} + 8 y^{^{'}} + 80 y = 40 cos (8 x)

y^{^{''''}} - 4 y^{^{''}} = x^{2} + 3 e^{x}

y^{^{''}} - 10 y^{^{'}} + 25 y = \frac{e ^{5 x}}{9 + x ^{2}}

What is the solution for y^{''}-y=1.7sin(t) ?
The solution for y^{''}-y=1.7sin(t) is y=c_{1}e^t+c_{2}e^{-t}-0.85sin(t)