What is the solution for y^{''}-4y=2e^{4t} ?

The solution for y^{''}-4y=2e^{4t} is y=c_{1}e^{2t}+c_{2}e^{-2t}+1/6 e^{4t}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-4y=2e^{4t}

y^{^{''}} - 4 y = 2 e^{4 t}

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + \frac{1}{6} e^{4 t}

Solution steps

y^{''} (t) - 4 y = 2 e^{4 t}

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + \frac{1}{6} e^{4 t}

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + \frac{1}{6} e^{4 t}

y^{^{''}} - 6 y^{^{'}} + 9 y = 25 e^{t} sin (t)

(D^{2} + 7 D + 6) y = e^{2 x}

y^{^{''}} - 2 y^{^{'}} + y = ln (x)

y^{^{''}} = 2 y + 18 tan^{3} (x)

y^{^{''}} + 2 y^{^{'}} - 2 y = e^{- 2 x} (3 x^{2} + 5 x + 2)

What is the solution for y^{''}-4y=2e^{4t} ?
The solution for y^{''}-4y=2e^{4t} is y=c_{1}e^{2t}+c_{2}e^{-2t}+1/6 e^{4t}