What is the solution for y^{''}+2y^'=6x^2+2x+3 ?

The solution for y^{''}+2y^'=6x^2+2x+3 is y=c_{1}+c_{2}e^{-2x}+x^3-x^2+(5x)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+2y^'=6x^2+2x+3

y^{^{''}} + 2 y^{^{'}} = 6 x^{2} + 2 x + 3

y = c_{1} + c_{2} e^{- 2 x} + x^{3} - x^{2} + \frac{5 x}{2}

Solution steps

y^{''} (x) + 2 y^{'} (x) = 6 x^{2} + 2 x + 3

Solve linear ODE:

y = c_{1} + c_{2} e^{- 2 x} + x^{3} - x^{2} + \frac{5 x}{2}

y = c_{1} + c_{2} e^{- 2 x} + x^{3} - x^{2} + \frac{5 x}{2}

y^{^{''}} + 4 y^{^{'}} + 4 y = - 4 x

y^{^{''}} + 3 y^{^{'}} + 2 y = 4 cos (x)

y^{^{''}} + 4 \cdot y^{^{'}} + 4 \cdot y = 20 cos (2 t)

y^{^{''}} + 12 y^{^{'}} + 36 y = e^{- 6 t} ln (t)

y^{^{''}} - 4 y^{^{'}} = 2 x^{2} + 5

What is the solution for y^{''}+2y^'=6x^2+2x+3 ?
The solution for y^{''}+2y^'=6x^2+2x+3 is y=c_{1}+c_{2}e^{-2x}+x^3-x^2+(5x)/2