What is the solution for y^{''}+4y^'=4-4e^{-4x} ?

The solution for y^{''}+4y^'=4-4e^{-4x} is y=c_{1}+c_{2}e^{-4x}+x+e^{-4x}x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+4y^'=4-4e^{-4x}

y^{^{''}} + 4 y^{^{'}} = 4 - 4 e^{- 4 x}

y = c_{1} + c_{2} e^{- 4 x} + x + e^{- 4 x} x

Solution steps

y^{''} (x) + 4 y^{'} (x) = 4 - 4 e^{- 4 x}

Solve linear ODE:

y = c_{1} + c_{2} e^{- 4 x} + x + e^{- 4 x} x

y = c_{1} + c_{2} e^{- 4 x} + x + e^{- 4 x} x

y^{^{''}} + y^{^{'}} - 6 y = 4 t e^{2 t}

y^{^{''}} - 9 y = e^{3 x}, y (0) = 3, y^{^{'}} (0) = 10

y^{^{''}} - 4 y^{^{'}} + 4 y = e^{2 x} + cos (2 x)

\frac{x ^{^{''}}}{2} + 10 x^{^{'}} + 100 x = 150

y^{^{''}} + a y^{^{'}} + b y = t + e^{3 t}

What is the solution for y^{''}+4y^'=4-4e^{-4x} ?
The solution for y^{''}+4y^'=4-4e^{-4x} is y=c_{1}+c_{2}e^{-4x}+x+e^{-4x}x