What is the solution for y^{''}+y-pi/2 =0 ?

The solution for y^{''}+y-pi/2 =0 is y=c_{1}cos(t)+c_{2}sin(t)+pi/2

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y^{''}+y-pi/2 =0

y^{^{''}} + y - \frac{π}{2} = 0

y = c_{1} cos (t) + c_{2} sin (t) + \frac{π}{2}

Solution steps

y^{''} (t) + y - \frac{π}{2} = 0

Solve linear ODE:

y = c_{1} cos (t) + c_{2} sin (t) + \frac{π}{2}

y = c_{1} cos (t) + c_{2} sin (t) + \frac{π}{2}

y^{^{''''}} - 2 y^{^{''}} + y = 100 cos (3 x)

y^{^{''}} - 3 y^{^{'}} - 40 y = 168 e^{2 t}

y^{^{'''}} - y^{^{''}} - 4 y^{^{'}} + 4 y = sin (x)

y^{^{''}} + b y = a

y^{^{''}} + y^{^{'}} + x = 0

What is the solution for y^{''}+y-pi/2 =0 ?
The solution for y^{''}+y-pi/2 =0 is y=c_{1}cos(t)+c_{2}sin(t)+pi/2