What is the solution for y^{''}-18y^'+117y=0 ?

The solution for y^{''}-18y^'+117y=0 is y=e^{9t}(c_{1}cos(6t)+c_{2}sin(6t))

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y^{''}-18y^'+117y=0

y^{^{''}} - 18 y^{^{'}} + 117 y = 0

y = e^{9 t} (c_{1} cos (6 t) + c_{2} sin (6 t))

Solution steps

y^{''} (t) - 18 y^{'} (t) + 117 y = 0

Solve linear ODE:

y = e^{9 t} (c_{1} cos (6 t) + c_{2} sin (6 t))

y = e^{9 t} (c_{1} cos (6 t) + c_{2} sin (6 t))

x \to \frac{1}{2} lim (\frac{x + 4}{2 x})

\frac{d}{d x} (\frac{3}{x + 2})

\int \frac{4}{y ^{2} + 5 y - 14} d y

\int_{0}^{21} - x (x - 21) (x + 1) d x

\frac{d}{d x} ((x)^{x})

What is the solution for y^{''}-18y^'+117y=0 ?
The solution for y^{''}-18y^'+117y=0 is y=e^{9t}(c_{1}cos(6t)+c_{2}sin(6t))