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Popular >

derivative of c_{1}cos(2x+c_{2}sin(2x))

Solution

\frac{d}{d x} (c_{1} cos (2 x) + c_{2} sin (2 x))

Solution

- 2 c_{1} sin (2 x) + c_{2} cos (2 x) \cdot 2

Solution steps

\frac{d}{d x} (c_{1} cos (2 x) + c_{2} sin (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (c_{1} cos (2 x)) + \frac{d}{d x} (c_{2} sin (2 x))

\frac{d}{d x} (c_{1} cos (2 x)) = - 2 c_{1} sin (2 x)

\frac{d}{d x} (c_{2} sin (2 x)) = c_{2} cos (2 x) \cdot 2

= - 2 c_{1} sin (2 x) + c_{2} cos (2 x) \cdot 2

Popular Examples

derivative of sec(1/2 xtan(1/2 x))

\frac{d}{d x} (sec (\frac{1}{2} x) tan (\frac{1}{2} x))

derivative of a/(x^2+b)

\frac{d}{d x} (\frac{a}{x ^{2} + b})

derivative of y=x^8 derivative of

y = x^{8}

d/(dy)(x^2+2xy+y^2)

\frac{d}{d y} (x^{2} + 2 x y + y^{2})

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\int x cos (\frac{nπ x}{l}) d x

Frequently Asked Questions (FAQ)

What is the derivative of c_{1}cos(2x+c_{2}sin(2x)) ?
The derivative of c_{1}cos(2x+c_{2}sin(2x)) is -2c_{1}sin(2x)+c_{2}cos(2x)*2
What is the first derivative of c_{1}cos(2x+c_{2}sin(2x)) ?
The first derivative of c_{1}cos(2x+c_{2}sin(2x)) is -2c_{1}sin(2x)+c_{2}cos(2x)*2