What is the solution for y^{''}+y=9cos(2x) ?

The solution for y^{''}+y=9cos(2x) is y=c_{1}cos(x)+c_{2}sin(x)-3cos(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+y=9cos(2x)

y^{^{''}} + y = 9 cos (2 x)

y = c_{1} cos (x) + c_{2} sin (x) - 3 cos (2 x)

Solution steps

y^{''} (x) + y = 9 cos (2 x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - 3 cos (2 x)

y = c_{1} cos (x) + c_{2} sin (x) - 3 cos (2 x)

y^{^{''}} - 12 y^{^{'}} + 36 y = 24 x + 2

y^{^{''}} + y = x^{2} + 1, y (0) = 5, y (1) = 0

y^{^{''}} + 25 y = 10 sin (5 t)

y^{^{''}} - 12 y^{^{'}} + 36 y = 12 x + 6

y^{^{''}} - 12 y^{^{'}} + 36 y = 36 x + 2

What is the solution for y^{''}+y=9cos(2x) ?
The solution for y^{''}+y=9cos(2x) is y=c_{1}cos(x)+c_{2}sin(x)-3cos(2x)