What is the solution for 2xy^'+y=2sqrt(x) ?

The solution for 2xy^'+y=2sqrt(x) is y=sqrt(x)+(c_{1})/(sqrt(x))

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2xy^'+y=2sqrt(x)

2 x y^{^{'}} + y = 2 x

y = x + \frac{c _{1}}{x}

Solution steps

2 x y^{'} (x) + y = 2 x

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y = x + \frac{c _{1}}{x}

y = x + \frac{c _{1}}{x}

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What is the solution for 2xy^'+y=2sqrt(x) ?
The solution for 2xy^'+y=2sqrt(x) is y=sqrt(x)+(c_{1})/(sqrt(x))