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Popular >

y^{''}-y^'-20=0

Solution

y^{^{''}} - y^{^{'}} - 20 = 0

Solution

y = c_{1} e^{t} + c_{2} - 20 t

Solution steps

y^{''} (t) - y^{'} (t) - 20 = 0

Solve linear ODE:

y = c_{1} e^{t} + c_{2} - 20 t

y = c_{1} e^{t} + c_{2} - 20 t

Graph

Popular Examples

(d^2y)/(dx^2)-9y=e^{3x}cos(2x)+e^{2x}

\frac{d ^{2} y}{d x ^{2}} - 9 y = e^{3 x} cos (2 x) + e^{2 x}

y^{''}+9y=cos(t)

y^{^{''}} + 9 y = cos (t)

y^{''}+4y^'+5y=e^{3x}

y^{^{''}} + 4 y^{^{'}} + 5 y = e^{3 x}

y^{''}+4y=t^3+3e^t,y(0)=0,y^'(0)=2

y^{^{''}} + 4 y = t^{3} + 3 e^{t}, y (0) = 0, y^{^{'}} (0) = 2

4y^{''}-y=12x+6x

4 y^{^{''}} - y = 12 x + 6 x

Frequently Asked Questions (FAQ)

What is the solution for y^{''}-y^'-20=0 ?
The solution for y^{''}-y^'-20=0 is y=c_{1}e^t+c_{2}-20t