What is the solution for y^{''}+y^'=1,y(0)=0,y^'(0)=1 ?

The solution for y^{''}+y^'=1,y(0)=0,y^'(0)=1 is y=t

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y^{''}+y^'=1,y(0)=0,y^'(0)=1

y^{^{''}} + y^{^{'}} = 1, y (0) = 0, y^{^{'}} (0) = 1

y = t

Solution steps

y^{''} (t) + y^{'} (t) = 1

Solve linear ODE:

y = t

y = t

y^{^{''}} - 4 y^{^{'}} + 4 y = e^{2 x} arctan (x)

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + 6 y = x^{2} + x

y^{^{''}} - 4 y^{^{'}} - 12 y = - 20 t + 24 t^{2}

(d^{2} - 4 d + 3) y = 2 x + 5

y^{^{''}} + y = 6 e^{x}

What is the solution for y^{''}+y^'=1,y(0)=0,y^'(0)=1 ?
The solution for y^{''}+y^'=1,y(0)=0,y^'(0)=1 is y=t