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Popular >

y^{''}+4y^'=2

Solution

y^{^{''}} + 4 y^{^{'}} = 2

Solution

y = c_{1} + c_{2} e^{- 4 t} + \frac{t}{2}

Solution steps

y^{''} (t) + 4 y^{'} (t) = 2

Solve linear ODE:

y = c_{1} + c_{2} e^{- 4 t} + \frac{t}{2}

y = c_{1} + c_{2} e^{- 4 t} + \frac{t}{2}

Graph

Popular Examples

(D^2+5D+6)y=e^{2x}

(D^{2} + 5 D + 6) y = e^{2 x}

25y^{''}-y=(xex)/5

25 y^{^{''}} - y = \frac{x e x}{5}

y^{''}-2y^'+y=e^x+e^{2x}

y^{^{''}} - 2 y^{^{'}} + y = e^{x} + e^{2 x}

y^{''}-2y^'+5y=e^x(0=(2x))

y^{^{''}} - 2 y^{^{'}} + 5 y = e^{x} (0 = (2 x))

y^{''}-6y^'+9y=18

y^{^{''}} - 6 y^{^{'}} + 9 y = 18

Frequently Asked Questions (FAQ)

What is the solution for y^{''}+4y^'=2 ?
The solution for y^{''}+4y^'=2 is y=c_{1}+c_{2}e^{-4t}+t/2